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2m^2-3=175
We move all terms to the left:
2m^2-3-(175)=0
We add all the numbers together, and all the variables
2m^2-178=0
a = 2; b = 0; c = -178;
Δ = b2-4ac
Δ = 02-4·2·(-178)
Δ = 1424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1424}=\sqrt{16*89}=\sqrt{16}*\sqrt{89}=4\sqrt{89}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{89}}{2*2}=\frac{0-4\sqrt{89}}{4} =-\frac{4\sqrt{89}}{4} =-\sqrt{89} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{89}}{2*2}=\frac{0+4\sqrt{89}}{4} =\frac{4\sqrt{89}}{4} =\sqrt{89} $
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